Tuesday 13 January 2015

Mathematics Formulas (गणित के सूत्र)

***कुछ महत्वपूर्ण गणित के सूत्र ***
»»»Algebra Related«««
1. (α+в)²= α²+2αв+в²
2. (α+в)²= (α-в)²+4αв b
3. (α-в)²= α²-2αв+в²
4. (α-в)²= f(α+в)²-4αв
5. α² + в²= (α+в)² - 2αв.
6. α² + в²= (α-в)² + 2αв.
7. α²-в² =(α + в)(α - в)
8. 2(α² + в²) = (α+ в)² + (α - в)²
9. 4αв = (α + в)² -(α-в)²
10. αв ={(α+в)/2}²-{(α-в)/2}²
11. (α + в + ¢)² = α² + в² + ¢² + 2(αв
+ в¢ + ¢α)
12. (α + в)³ = α³ + 3α²в + 3αв² + в³
13. (α + в)³ = α³ + в³ + 3αв(α + в)
14. (α-в)³=α³-3α²в+3αв²-в³
15. α³ + в³ = (α + в) (α² -αв + в²)
16. α³ + в³ = (α+ в)³ -3αв(α+ в)
17. α³ -в³ = (α -в) (α² + αв + в²)
18. α³ -в³ = (α-в)³ + 3αв(α-в)
19) (α+в+¢)²= α²+в²+¢²+2(αв+в¢+¢α)

»»»Trigonometri Related««»
1) ѕιη0° =0
2) ѕιη30° = 1/2
3) ѕιη45° = 1/√2
4) ѕιη60° = √3/2
5) ѕιη90° = 1
6) ¢σѕec ιѕ σρρσѕιтє σƒ ѕιη
7) тαη0° = 0
8) тαη30° = 1/√3
9) тαη45° = 1
10) тαη60° = √3
11) тαη90° = ∞
12) ¢σт ιѕ σρρσѕιтє σƒ тαη
13) ѕє¢0° = 1
14) ѕє¢30° = 2/√3
15) ѕє¢45° = √2
16) ѕє¢60° = 2
17) ѕє¢90° = ∞
18) ѕє¢ ιѕ σρρσѕιтє σƒ ¢os
19) 2ѕιηα¢σѕв=ѕιη(α+в)+ѕιη(α-в)
20) 2¢σѕαѕιηв=ѕιη(α+в)-ѕιη(α-в)
21) 2¢σѕα¢σѕв=¢σѕ(α+в)+¢σѕ(α-в)
22) 2ѕιηαѕιηв=¢σѕ(α-в)-¢σѕ(α+в)
23) ѕιη(α+в)=ѕιηα ¢σѕв+ ¢σѕα ѕιηв.
24) ¢σѕ(α+в)=¢σѕα ¢σѕв - ѕιηα ѕιηв.
25) ѕιη(α-в)=ѕιηα¢σѕв-¢σѕαѕιηв.
26)¢σѕ(α+в)=¢σѕα¢σѕв+ѕιηαѕιηв
27) тαη(α+в)= (тαηα + тαηв)/
(1−тαηαтαηв)
28) тαη(α−в)= (тαηα − тαηв) / (1+тαηαтαηв)
29) ¢σт(α+в)= (¢σтα¢σтв −1) / (¢σтα + ¢σтв)
30) ¢σт(α−в)= (¢σтα¢σтв + 1) / (¢σтв− ¢σтα)
31) ѕιη(α+в)=ѕιηα ¢σѕв+ ¢σѕα ѕιηв.
32) ¢σѕ(α+в)=¢σѕα ¢σѕв +ѕιηα ѕιηв.
33) ѕιη(α-в)=ѕιηα¢σѕв-¢σѕαѕιηв.
34)¢σѕ(α_в)=¢σѕα¢σѕв+ѕιηαѕιηв.
35) тαη(α+в)= (тαηα + тαηв)/
(1−тαηαтαηв)
36) тαη(α−в)= (тαηα − тαηв) / (1+
тαηαтαηв)
37) ¢σт(α+в)= (¢σтα¢σтв −1) / (¢σтα + ¢σтв)
38) ¢σт(α−в)= (¢σтα¢σтв + 1) / (¢σтв− ¢σтα)
39) α/ѕιηα = в/ѕιηв = ¢/ѕιη¢ = 2я
» α = в ¢σѕ¢ + ¢ ¢σѕв
» в = α ¢σѕ¢ + ¢ ¢σѕα
» ¢ = α ¢σѕв + в ¢σѕα
40) ¢σѕα = (в² + ¢²− α²) / 2в¢
41) ¢σѕв = (¢² + α²− в²) / 2¢α
42) ¢σѕ¢ = (α² + в²− ¢²) / 2¢α
43) Δ = αв¢/4я
» ѕιηΘ = 0 тнєη,Θ = ηΠ
» ѕιηΘ = 1 тнєη,Θ = (4η + 1)Π/2
» ѕιηΘ =−1 тнєη,Θ = (4η− 1)Π/2
» ѕιηΘ = ѕιηα тнєη,Θ = ηΠ (−1)^ηα
1. ѕιη2α = 2ѕιηα¢σѕα
2. ¢σѕ2α = ¢σѕ²α − ѕιη²α
3. ¢σѕ2α = 2¢σѕ²α − 1
4. ¢σѕ2α = 1 − ѕιη²α
5. 2ѕιη²α = 1 − ¢σѕ2α
6. 1 + ѕιη2α = (ѕιηα + ¢σѕα)²
7. 1 − ѕιη2α = (ѕιηα − ¢σѕα)²
8. тαη2α = 2тαηα / (1 − тαη²α)
9. ѕιη2α = 2тαηα / (1 + тαη²α)
10. ¢σѕ2α = (1 − тαη²α) / (1 + тαη²α)
11. 4ѕιη³α = 3ѕιηα − ѕιη3α
12. 4¢σѕ³α = 3¢σѕα + ¢σѕ3α

Saturday 3 January 2015

New Year 2015 Celebration in Success Coaching Hub

My wishes for you are not limited to just the next year but to all the years that you experience in your lifetime and in your reincarnations!

Have a fun-filled, smashing, rocking and happening New Years 2015